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Determine the value of
y, if
x is 6.

y=x^(2)+10
Answer:

Determine the value of $y$ , if $x$ is $6$ . $\newline$ $y=x^{2}+10$ $\newline$ Answer:

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Find the vertex of the transformed function

Full solution

Q. Determine the value of

y

, if

x

is

6

.

\newline

y=x^{2}+10

\newline

Answer:

Given Function: We are given the function $y = x^2 + 10$ and asked to find the value of $y$ when $x$ is $6$ . To find $y$ , we substitute $x$ with $6$ in the equation and calculate the result. $y = 6^2 + 10$
Substitute and Calculate: Now we calculate the square of $6$ , which is $6 \times 6$ . $6^2 = 36$
Calculate Square: Next, we add $10$ to the result of the square of $6$ to find the value of $y$ . $\newline$ $y = 36 + 10$
Add $10$ : Adding $36$ and $10$ gives us the final value of $y$ . $\newline$ $y = 46$

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