Determine the value of y, if x is 25 . y=sqrt(x+11) Answer: y=

Identify Values and Equation: Identify the given values and the equation to solve for y. We are given that x = 25 and the equation y = sqrt(x + 11). We need to substitute the value of x into the equation to find y.Substitute Value into Equation: Substitute the value of x into the equation. Substitute x = 25 into y = sqrt(x + 11) to get y = sqrt(25 + 11).Perform Addition Inside Square Root: Perform the addition inside the square root. Calculate the sum inside the square root: 25 + 11 = 36.Calculate Square Root: Calculate the square root of the sum to find the value of y. Find the square root of 36, which is y = sqrt(36).Determine Final Value: Determine the square root of 36. Since the square root of 36 is 6, we have y = 6.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Determine the value of
y, if
x is 25 .

y=sqrt(x+11)
Answer:
y=

Determine the value of $y$ , if $x$ is $25$ . $\newline$ $y=\sqrt{x+11}$ $\newline$ Answer: $y=$

View step-by-step help

Home

Math Problems

Precalculus

Find trigonometric ratios using multiple identities

Full solution

Q. Determine the value of

y

, if

x

25

\newline

y=\sqrt{x+11}

\newline

Answer:

y=

Identify Values and Equation: Identify the given values and the equation to solve for $y$ . We are given that $x = 25$ and the equation $y = \sqrt{x + 11}$ . We need to substitute the value of $x$ into the equation to find $y$ .
Substitute Value into Equation: Substitute the value of $x$ into the equation. $\newline$ Substitute $x = 25$ into $y = \sqrt{x + 11}$ to get $y = \sqrt{25 + 11}$ .
Perform Addition Inside Square Root: Perform the addition inside the square root. $\newline$ Calculate the sum inside the square root: $25 + 11 = 36$ .
Calculate Square Root: Calculate the square root of the sum to find the value of $y$ . Find the square root of $36$ , which is $y = \sqrt{36}$ .
Determine Final Value: Determine the square root of $36$ . Since the square root of $36$ is $6$ , we have $y = 6$ .