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Determine the intercepts of the line.
Do not round your answers.

{:[y=11 x+6],[x"-intercept: "(◻","◻)],[y"-intercept: "(◻","◻)]:}

Determine the intercepts of the line.\newlineDo not round your answers.\newliney=11x+6x-intercept: (,)y-intercept: (,) \begin{array}{l} y=11 x+6 \\ x \text {-intercept: }(\square, \square) \\ y \text {-intercept: }(\square, \square) \end{array}

Full solution

Q. Determine the intercepts of the line.\newlineDo not round your answers.\newliney=11x+6x-intercept: (,)y-intercept: (,) \begin{array}{l} y=11 x+6 \\ x \text {-intercept: }(\square, \square) \\ y \text {-intercept: }(\square, \square) \end{array}
  1. Find x-intercept: To find the x-intercept, we set yy to 00 and solve for xx.0=11x+60 = 11x + 6Subtract 66 from both sides to isolate the term with xx.6=11x-6 = 11xDivide both sides by 1111 to solve for xx.x=611x = -\frac{6}{11}
  2. X-intercept point: The xx-intercept is the point where the line crosses the xx-axis, so the yy-coordinate is 00. Therefore, the xx-intercept is (611,0)(-\frac{6}{11}, 0).
  3. Find y-intercept: To find the y-intercept, we set xx to 00 and solve for yy.\newliney=11(0)+6y = 11(0) + 6\newliney=0+6y = 0 + 6\newline$y = \(6\)
  4. Y-intercept point: The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is \(0\). Therefore, the y-intercept is \((0, 6)\).

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