Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).x→∞lim5x2+8x4+1064x8−23x6Answer:
Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).x→∞lim5x2+8x4+1064x8−23x6Answer:
Factor out x8: We are given the limit:x→∞lim(5x2+8x4+1064x8−23x6)To simplify this limit, we will first factor out the highest power of x in the numerator and denominator.
Factor out x4: In the numerator, the highest power of x inside the square root is x8. We factor out x8 from the square root, which is equivalent to x4 outside the square root.64x8−23x6=x8(64−23/x2)=x4⋅64−23/x2
Rewrite with factored terms: In the denominator, the highest power of x is x4. We factor out x4 from each term.5x2+8x4+10=x4(x25+8+x410)
Cancel out x4 terms: Now we rewrite the limit with the factored terms: limx→∞(x4(x25+8+x410)x464−x223)
Remove terms with x: We can now cancel out the x4 terms in the numerator and denominator: limx→∞(x25+8+x41064−x223)
Simplify square root: As x approaches infinity, the terms with x in the denominator approach zero. Therefore, we can simplify the limit further by removing those terms:limx→∞(64)/(8)
Division of constants: The square root of 64 is 8, so the limit simplifies to:limx→∞(88)
Division of constants: The square root of 64 is 8, so the limit simplifies to:x→∞lim88The limit of a constant over a constant is just the division of those constants:x→∞lim88=1