Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).x→∞lim7+7x2327x6−14x3Answer:
Factor out highest power: We are given the limit expression:limx→∞(327x6−14x3)/(7+7x2)To simplify this expression, we will first factor out the highest power of x in the numerator and denominator.
Factor out x6: In the numerator, the highest power of x inside the cube root is x6. We factor out x6 from each term inside the cube root:327x6−14x3=3x6(27−14/x3)
Take x2 outside: Now we take x(6) outside of the cube root, remembering that when we take a power out of a root, we divide the exponent by the root index: \sqrt[\(3]{x^{(6)}(27−14/x^{(3)})} = x^{(6/3)} * \sqrt[3]{27−14/x^{(3)}} = x^2 * \sqrt[3]{27−14/x^{(3)}}
Factor out x2: In the denominator, we factor out x2 from each term: 7+7x2=7(1+x2)
Rewrite with factored terms: Now we rewrite the limit expression with the factored terms: limx→∞(7(1+x2)x2327−x314)
Divide by x2: We can now divide both the numerator and the denominator by x2:x→∞lim(7(1+x2)/x2x2/x2⋅327−14/x3)
Simplify expression: Simplifying the expression by canceling out x2 in the numerator and dividing each term in the denominator by x2 gives us:x→∞lim(327−x314)/(x27+7)
Approach infinity: As x approaches infinity, x314 approaches 0 and x27 also approaches 0. Therefore, the limit simplifies to:limx→∞(7327)
Simplify further: The cube root of 27 is 3, so the limit simplifies further to: limx→∞73
Final limit: Since 73 is a constant, the limit as x approaches infinity is simply 73.