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Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).

lim_(x rarr oo)(root(3)(27x^(6)-14x^(3)))/(7+7x^(2))
Answer:

Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx27x614x337+7x2 \lim _{x \rightarrow \infty} \frac{\sqrt[3]{27 x^{6}-14 x^{3}}}{7+7 x^{2}} \newlineAnswer:

Full solution

Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx27x614x337+7x2 \lim _{x \rightarrow \infty} \frac{\sqrt[3]{27 x^{6}-14 x^{3}}}{7+7 x^{2}} \newlineAnswer:
  1. Factor out highest power: We are given the limit expression:\newlinelimx(27x614x33)/(7+7x2)\lim_{x \to \infty}(\sqrt[3]{27x^{6}-14x^{3}})/(7+7x^{2})\newlineTo simplify this expression, we will first factor out the highest power of xx in the numerator and denominator.
  2. Factor out x6x^6: In the numerator, the highest power of xx inside the cube root is x6x^6. We factor out x6x^6 from each term inside the cube root:\newline27x614x33=x6(2714/x3)3\sqrt[3]{27x^{6}-14x^{3}} = \sqrt[3]{x^{6}(27-14/x^{3})}
  3. Take x2x^2 outside: Now we take x(6)x^{(6)} outside of the cube root, remembering that when we take a power out of a root, we divide the exponent by the root index: \sqrt[\(3]{x^{(66)}(272714-14/x^{(33)})} = x^{(66/33)} * \sqrt[33]{272714-14/x^{(33)}} = x^22 * \sqrt[33]{272714-14/x^{(33)}}
  4. Factor out x2x^2: In the denominator, we factor out x2x^2 from each term: 7+7x2=7(1+x2)7+7x^{2} = 7(1+x^{2})
  5. Rewrite with factored terms: Now we rewrite the limit expression with the factored terms: limx(x22714x337(1+x2))\lim_{x \to \infty}\left(\frac{x^2 \sqrt[3]{27-\frac{14}{x^{3}}}}{7(1+x^{2})}\right)
  6. Divide by x2x^2: We can now divide both the numerator and the denominator by x2x^2:limx(x2/x22714/x337(1+x2)/x2)\lim_{x \to \infty}\left(\frac{x^2/x^2 \cdot \sqrt[3]{27-14/x^{3}}}{7(1+x^{2})/x^2}\right)
  7. Simplify expression: Simplifying the expression by canceling out x2x^2 in the numerator and dividing each term in the denominator by x2x^2 gives us:\newlinelimx(2714x33)/(7x2+7)\lim_{x \to \infty}\left(\sqrt[3]{27-\frac{14}{x^{3}}}\right)/\left(\frac{7}{x^2}+7\right)
  8. Approach infinity: As xx approaches infinity, 14x3\frac{14}{x^{3}} approaches 00 and 7x2\frac{7}{x^2} also approaches 00. Therefore, the limit simplifies to:\newlinelimx(2737)\lim_{x \to \infty}\left(\frac{\sqrt[3]{27}}{7}\right)
  9. Simplify further: The cube root of 2727 is 33, so the limit simplifies further to: limx37\lim_{x \to \infty}\frac{3}{7}
  10. Final limit: Since 37\frac{3}{7} is a constant, the limit as xx approaches infinity is simply 37\frac{3}{7}.

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