Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).x→∞lim7+6x264x6+12x5+42x4Answer:
Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).x→∞lim7+6x264x6+12x5+42x4Answer:
Factor Out Highest Power: We are given the limit expression limx→∞(7+6x264x6+12x5+42x4). To simplify this, we will first factor out the highest power of x in the numerator inside the square root.
Factor Out x6: Factor out x6 from the square root in the numerator to simplify the expression inside the square root.64x6+12x5+42x4=x6(64+12/x+42/x2)
Take x3 Out: Now, we can take x3 out of the square root, since x6=x3.x6(64+12/x+42/x2)=x364+12/x+42/x2
Divide by x2: Next, we will divide both the numerator and the denominator by x2, the highest power of x in the denominator.7+6x2x364+x12+x242=64+x12+x242x3/x27/x2+61
Simplify Expression: Simplify the expression by canceling out x2 from x2x3 and simplifying the square root as x approaches infinity.\frac{x^{\(3\)}}{x^{\(2\)}}\left(\sqrt{\(64\)+\frac{\(12\)}{x}+\frac{\(42\)}{x^{\(2\)}}}\right)\div\left(\frac{\(7\)}{x^{\(2\)}}+\(6\right) = x\left(\sqrt{64+\frac{12}{x}+\frac{42}{x^{2}}}\right)\div\left(\frac{7}{x^{2}}+6\right)
Approach Infinity: As x approaches infinity, the terms x12, x242, and x27 in the expression will approach 0.x27+6x(64+x12+x242) = 0+6x(64+0+0)
Find Limit: Now we have a simplified expression where we can easily find the limit as x approaches infinity.6x64=6x(8)=34x
Find Limit: Now we have a simplified expression where we can easily find the limit as x approaches infinity.6x64=6x(8)=34xThe limit of 34x as x approaches infinity is infinity, which means the limit does not exist (DNE).x→∞lim(34x)=∞