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Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).

lim_(x rarr oo)(sqrt(-2+49x^(4)))/(3x+10x^(3))
Answer:

Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx2+49x43x+10x3 \lim _{x \rightarrow \infty} \frac{\sqrt{-2+49 x^{4}}}{3 x+10 x^{3}} \newlineAnswer:

Full solution

Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx2+49x43x+10x3 \lim _{x \rightarrow \infty} \frac{\sqrt{-2+49 x^{4}}}{3 x+10 x^{3}} \newlineAnswer:
  1. Identify highest power: We are asked to find the limit of the function (2+49x4)/(3x+10x3)(\sqrt{-2+49x^{4}})/(3x+10x^{3}) as xx approaches infinity. To do this, we will first identify the highest power of xx in both the numerator and the denominator.
  2. Divide by x3x^3: The highest power of xx in the numerator inside the square root is x4x^4, and in the denominator, it is x3x^3. To simplify the limit, we will divide both the numerator and the denominator by x3x^3, the highest power in the denominator.
  3. Simplify expression: Dividing each term by x3x^3 gives us the following expression:\newlinelimx(2x3+49x3+(10x2))\lim_{x \rightarrow \infty}\left(\frac{\sqrt{\frac{-2}{x^3}+49x}}{3+(10x^2)}\right)
  4. Take square root: As xx approaches infinity, the term (2x3)(-\frac{2}{x^3}) approaches 00, so we can simplify the expression to: limx(49x3+(10x2))\lim_{x \to \infty}\left(\frac{\sqrt{49x}}{3+(10x^2)}\right)
  5. Divide by x1/2x^{1/2}: We can take the square root of 49x49x, which is 7x1/27x^{1/2}, and rewrite the expression as:\newlinelimx7x1/23+(10x2)\lim_{x \to \infty}\frac{7x^{1/2}}{3+(10x^2)}
  6. Approach infinity: Now, we divide the numerator and the denominator by x1/2x^{1/2}, the highest power of xx in the numerator: limx(73/x1/2+10x3/2)\lim_{x \rightarrow \infty}\left(\frac{7}{3/x^{1/2}+10x^{3/2}}\right)
  7. Limit is 00: As xx approaches infinity, the term 3x12\frac{3}{x^{\frac{1}{2}}} approaches 00, and we are left with: limx710x32\lim_{x \rightarrow \infty}\frac{7}{10x^{\frac{3}{2}}}
  8. Limit is 00: As xx approaches infinity, the term (3/x1/2)(3/x^{1/2}) approaches 00, and we are left with:\newlinelimx710x3/2\lim_{x \rightarrow \infty}\frac{7}{10x^{3/2}}Now, as xx approaches infinity, the denominator (10x3/2)(10x^{3/2}) grows without bound, and the entire expression approaches 00. Therefore, the limit is 00.

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