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Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).

lim_(x rarr oo)(sqrt(64x^(9)+39 x+39x^(8)))/(9x+2x^(4)+4x^(2))
Answer:

Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx64x9+39x+39x89x+2x4+4x2 \lim _{x \rightarrow \infty} \frac{\sqrt{64 x^{9}+39 x+39 x^{8}}}{9 x+2 x^{4}+4 x^{2}} \newlineAnswer:

Full solution

Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx64x9+39x+39x89x+2x4+4x2 \lim _{x \rightarrow \infty} \frac{\sqrt{64 x^{9}+39 x+39 x^{8}}}{9 x+2 x^{4}+4 x^{2}} \newlineAnswer:
  1. Identify highest power: We are given the limit: \newlinelimx(64x9+39x+39x8)/(9x+2x4+4x2)\lim_{x \to \infty}(\sqrt{64x^{9}+39x+39x^{8}})/(9x+2x^{4}+4x^{2})\newlineTo simplify the limit, we will first identify the highest power of xx in the numerator and the denominator.
  2. Divide by x4x^4: The highest power of xx in the numerator inside the square root is x9x^9, and the highest power of xx in the denominator is x4x^4. To simplify the expression, we will divide both the numerator and the denominator by x4x^{4}.
  3. Rewrite the limit: We rewrite the limit as: limx(64x9x4+39xx4+39x8x49xx4+2x4x4+4x2x4)\lim_{x \to \infty}\left(\frac{\sqrt{\frac{64x^{9}}{x^{4}}+\frac{39x}{x^{4}}+\frac{39x^{8}}{x^{4}}}}{\frac{9x}{x^{4}}+\frac{2x^{4}}{x^{4}}+\frac{4x^{2}}{x^{4}}}\right)
  4. Simplify terms: Simplify the terms inside the square root and the terms in the denominator: limx(64x5+39x3+39x49x3+2+4x2)\lim_{x \to \infty}\left(\frac{\sqrt{64x^{5}+\frac{39}{x^{3}}+39x^{4}}}{\frac{9}{x^{3}}+2+\frac{4}{x^{2}}}\right)
  5. Ignore negative powers: As xx approaches infinity, the terms with negative powers of xx will approach zero. Therefore, we can ignore 39x3\frac{39}{x^{3}} in the numerator and 9x3\frac{9}{x^{3}} and 4x2\frac{4}{x^{2}} in the denominator.\newlinelimx(64x5+39x42)\lim_{x \to \infty}\left(\frac{\sqrt{64x^{5}+39x^{4}}}{2}\right)
  6. Take square root: Now, we can take the square root of the leading term in the numerator, which is 64x564x^{5}, since the other term, 39x439x^{4}, becomes negligible as xx approaches infinity.\newlinelimx(64x52)\lim_{x \to \infty}\left(\frac{\sqrt{64x^{5}}}{2}\right)
  7. Simplify expression: The square root of 64x564x^{5} is 8x528x^{\frac{5}{2}}. So the limit simplifies to: limx8x522\lim_{x \to \infty}\frac{8x^{\frac{5}{2}}}{2}
  8. Divide by 22: Simplify the expression by dividing 8x528x^{\frac{5}{2}} by 22:limx(4x52)\lim_{x \to \infty}(4x^{\frac{5}{2}})
  9. Limit is infinite: Since x5/2x^{5/2} grows without bound as xx approaches infinity, the limit is infinite. Therefore, the limit does not exist (DNE).

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