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Let’s check out your problem:
Use the following function rule to find
f
(
12
)
f(12)
f
(
12
)
.
\newline
f
(
x
)
=
(
−
1
−
3
x
)
2
f(x) = (-1-3 x)^{2}
f
(
x
)
=
(
−
1
−
3
x
)
2
\newline
f
(
12
)
=
□
f(12) = \square
f
(
12
)
=
□
View step-by-step help
Home
Math Problems
Algebra 1
Multiplication with rational exponents
Full solution
Q.
Use the following function rule to find
f
(
12
)
f(12)
f
(
12
)
.
\newline
f
(
x
)
=
(
−
1
−
3
x
)
2
f(x) = (-1-3 x)^{2}
f
(
x
)
=
(
−
1
−
3
x
)
2
\newline
f
(
12
)
=
□
f(12) = \square
f
(
12
)
=
□
Substitute
x
x
x
with
12
12
12
:
First, substitute
x
x
x
with
12
12
12
in the function rule.
f
(
12
)
=
(
−
1
−
3
×
12
)
2
f(12) = (-1 - 3\times12)^2
f
(
12
)
=
(
−
1
−
3
×
12
)
2
Calculate value inside parentheses:
Now, calculate the value inside the parentheses.
\newline
−
1
−
3
×
12
=
−
1
−
36
-1 - 3 \times 12 = -1 - 36
−
1
−
3
×
12
=
−
1
−
36
Simplify expression inside parentheses:
Then, simplify the expression inside the parentheses.
\newline
−
1
−
36
=
−
37
-1 - 36 = -37
−
1
−
36
=
−
37
Raise to the power of
2
2
2
:
Next, raise
−
37
-37
−
37
to the power of
2
2
2
.
(
−
37
)
2
=
1369
(-37)^2 = 1369
(
−
37
)
2
=
1369
Write down
f
(
12
)
f(12)
f
(
12
)
:
Finally, write down the value of
f
(
12
)
f(12)
f
(
12
)
.
\newline
f
(
12
)
=
1369
f(12) = 1369
f
(
12
)
=
1369
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or
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\newline
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\newline
\newline
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A
A
A
or
A
B
\frac{A}{B}
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, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
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\newline
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\newline
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\newline
Write your answer in the form
A
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or
A
B
\frac{A}{B}
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, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
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