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Use the following function rule to find f(88).
f(x)=10sqrt(56+x)
f(88)=◻

Use the following function rule to find f(88) f(88) .\newlinef(x)=1056+xf(x)=10 \sqrt{56+x}\newlinef(88)=f(88)=\square

Full solution

Q. Use the following function rule to find f(88) f(88) .\newlinef(x)=1056+xf(x)=10 \sqrt{56+x}\newlinef(88)=f(88)=\square
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=1056+xf(x) = 10\sqrt{56 + x} and we need to find the value of f(88)f(88).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(88)f(88), we substitute xx with 8888 in the function:\newlinef(88)=1056+88f(88) = 10\sqrt{56 + 88}
  3. Perform Addition Inside Square Root: Perform the addition inside the square root.\newlineCalculate the value inside the square root:\newline56+88=14456 + 88 = 144
  4. Evaluate Square Root: Evaluate the square root.\newlineThe square root of 144144 is 1212, since 12×12=14412 \times 12 = 144.\newline144=12\sqrt{144} = 12
  5. Multiply by 1010: Multiply the result by 1010. Now, multiply the square root result by 1010 to find f(88)f(88): f(88)=10×12f(88) = 10 \times 12
  6. Calculate Final Result: Calculate the final result.\newlineThe final result is:\newlinef(88)=120f(88) = 120

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