Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Daniela has a three-season acting contract for a new TV show. Her pay for Season 11 is pp dollars. Then, her pay will increase by 5%5\% from Season 11 to Season 22 and by 10%10\% from Season 22 to Season 33. Which of the following represents Daniela's Season 33 pay in terms of pp?\newline Choose 11 answer:\newline (A) 1.15p1.15p\newline (B) p1.15\frac{p}{1.15}\newline (C) (1.05)(1.1)p(1.05)(1.1)p\newline (D) p(1.05)(1.1)\frac{p}{(1.05)(1.1)}

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Evaluate functionsright chevron icon

Full solution

Q. Daniela has a three-season acting contract for a new TV show. Her pay for Season 11 is pp dollars. Then, her pay will increase by 5%5\% from Season 11 to Season 22 and by 10%10\% from Season 22 to Season 33. Which of the following represents Daniela's Season 33 pay in terms of pp?\newline Choose 11 answer:\newline (A) 1.15p1.15p\newline (B) p1.15\frac{p}{1.15}\newline (C) (1.05)(1.1)p(1.05)(1.1)p\newline (D) p(1.05)(1.1)\frac{p}{(1.05)(1.1)}
  1. Calculate Season 22 Pay: Daniela's pay for Season 11 is pp dollars. To find her pay for Season 22, we need to increase pp by 55 percent. To calculate a 55 percent increase, we multiply pp by 1.051.05 (since 55 percent is 0.050.05 and adding this to 11 gives us the total amount after the increase).\newlineSeason 22 pay = p×1.05p \times 1.05
  2. Calculate Season 33 Pay: Next, we need to calculate the pay for Season 33, which is a 10%10\% increase from Season 22. To find a 10%10\% increase, we multiply the Season 22 pay by 1.101.10 (since 10%10\% is 0.100.10 and adding this to 11 gives us the total amount after the increase).\newlineSeason 33 pay =Season 2 pay×1.10= \text{Season 2 pay} \times 1.10
  3. Substitute and Simplify: Substitute the expression for Season 22 pay into the equation for Season 33 pay.\newlineSeason 33 pay = (p×1.05)×1.10(p \times 1.05) \times 1.10
  4. Find Total Multiplier: Now, we multiply the two factors to find the total multiplier for pp to get the Season 33 pay.\newlineSeason 33 pay = p×(1.05×1.10)p \times (1.05 \times 1.10)
  5. Perform Final Multiplication: Perform the multiplication of the two factors.\newlineSeason 33 pay = p×1.155p \times 1.155

More problems from Evaluate functions

Question
What is the domain of this function?\newline(9,–2)(6,–10)(–3,9)(5,2)(9,–2)(6,–10)(–3,9)(5,2)\newlineChoices:\newline(A){–3,5,6,9}(B){–10,–2,2,9}(C){2,5,6,9}(D){–6,–3,5,9}(A)\{–3,5,6,9\}\newline(B)\{–10,–2,2,9\}\newline(C)\{2,5,6,9\}\newline(D)\{–6,–3,5,9\}
Get tutor helpright-arrow

Posted 7 months ago

Question
Look at this set of ordered pairs:\newline(2,14)(2, 14)\newline(10,12)(10, 12)\newline(3,−19)(3, -19)\newlineIs this relation a function?\newlineChoices:\newline[[yes]\text{[[yes]}[no]]\text{[no]]}
Get tutor helpright-arrow

Posted 7 months ago

Question
Use the following function rule to find f(11) f(11) .\newlinef(x)=−10−7x f(x) = -10 - 7x \newlinef(11)= f(11) = _____
Get tutor helpright-arrow

Posted 7 months ago

Question
Find the slope of the line y=−3x−25 y = -3x - \frac{2}{5} .\newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____\_\_\_\_\_
Get tutor helpright-arrow

Posted 7 months ago

Question
A line has a slope of 33 and passes through the point (−2,−10)(-2,-10). Write its equation in slope-intercept form.\newlineWrite your answer using integers, proper fractions, and improper fractions in simplest form.
Get tutor helpright-arrow

Posted 7 months ago

Question
What is the range of this function?\newliney = |x|\newlineChoices:\newlineall real numbers\text{all real numbers}\newline{y∣y≥0}\{y \mid y \geq 0\}\newline{y∣y≤0}\{y \mid y \leq 0\}\newline{y∣y>0}\{y \mid y > 0\}
Get tutor helpright-arrow

Posted 9 months ago

Question
Find g(x) g(x) , where g(x) g(x) is the translation 1 1 unit down of f(x)=∣x∣ f(x) = |x| .\newlineWrite your answer in the form a∣x−h∣+k a|x - h| + k , where a a , h h , and k k are integers.\newlineg(x)= g(x) = ______\newline
Get tutor helpright-arrow

Posted 9 months ago

Question
What is the domain of this function?\newline(8,–1)(7,–11)(–4,10)(4,3)(8,–1)(7,–11)(–4,10)(4,3)\newlineChoices: \newline(A){–4,4,7,8}(A)\{–4,4,7,8\}\newline(B){–11,–1,3,10}(B)\{–11,–1,3,10\}\newline(C){3,4,7,8}(C)\{3,4,7,8\}\newline(D){–7,–4,4,8}(D)\{–7,–4,4,8\}
Get tutor helpright-arrow

Posted 9 months ago

Question
What is the domain of this function?\newline(10, –3)(2, –9)(–5, 8)(3, 1)(10,\,–3)(2,\,–9)(–5,\,8)(3,\,1)\newlineChoices:\newline[{–5,2,3,10}][{–9, –3,1,8}][{1,2,3,10}][{–10, –5,2,3}][\{–5,2,3,10\}][\{–9,\,–3,1,8\}][\{1,2,3,10\}][\{–10,\,–5,2,3\}]
Get tutor helpright-arrow

Posted 7 months ago

Question
What is the domain of this function?\newline(1,–4)(9,–12)(–6,11)(7,5)(1,–4)(9,–12)(–6,11)(7,5)\newlineChoices:(A){–6,1,7,9}\newline\\(A)\{–6,1,7,9\}\newline(B){–12,–4,5,11}(B)\{–12,–4,5,11\}\newline(C{5,1,7,9}(C\{5,1,7,9\}\newline(D){–9,–6,1,7}(D)\{–9,–6,1,7\}
Get tutor helpright-arrow

Posted 7 months ago

View all (97)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant