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d(n)=6-4(n-1)
Find the 
5^("th ") term in the sequence.

d(n)=64(n1) d(n)=6-4(n-1) \newlineFind the 5th  5^{\text {th }} term in the sequence.

Full solution

Q. d(n)=64(n1) d(n)=6-4(n-1) \newlineFind the 5th  5^{\text {th }} term in the sequence.
  1. Determine General Formula: Determine the general formula for the nnth term of the sequence.\newlineThe given formula is d(n)=64(n1)d(n)=6-4(n-1). This is an explicit formula for an arithmetic sequence where 66 is the first term and 4-4 is the common difference.
  2. Substitute n n with 5 5 : Substitute n n with 5 5 to find the 55th term.\newlineTo find the 55th term, we substitute n n with 5 5 in the formula: d(5)=64(51) d(5) = 6 - 4(5 - 1) .
  3. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newlineCalculate 515-1 which equals 44.
  4. Multiply Result by ext{4-4}: Multiply the result by ext{4-4}.\newlineMultiply ext{44} by ext{4-4} to get ext{16-16}.
  5. Add Result to 66: Add the result to 66.\newlineAdd 16 -16 to 66 to get the 55th term: 616=106 - 16 = -10.

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