d(n)=3(-2)^(n-1) What is the 4^("th ") term in the sequence?

Understand formula: Understand the given sequence formula. The formula d(n)=3(-2)^(n-1) defines a sequence where each term is generated by plugging in the position number n into the formula.Find 4th term: Plug in the value of n=4 to find the 4th term. We need to find d(4), which means we will substitute n with 4 in the formula. d(4)=3(-2)^(4-1)Simplify exponent: Simplify the exponent. Calculate the value of (-2)^(4-1), which is (-2)^3. (-2)^3 = -2 * -2 * -2 = -8Multiply by 3: Multiply the result by 3. Now, multiply the result from Step 3 by 3 as per the sequence formula. d(4) = 3 * (-8) = -24

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d(n)=3(-2)^(n-1)
What is the
4^("th ") term in the sequence?

$d(n)=3(-2)^{n-1}$ $\newline$ What is the $4^{\text {th }}$ term in the sequence?

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d(n)=3(-2)^{n-1}

\newline

What is the

4^{\text {th }}

term in the sequence?

Understand formula: Understand the given sequence formula. $\newline$ The formula $d(n)=3(-2)^{(n-1)}$ defines a sequence where each term is generated by plugging in the position number $n$ into the formula.
Find $4$ th term: Plug in the value of $n=4$ to find the $4$ th term. $\newline$ We need to find $d(4)$ , which means we will substitute $n$ with $4$ in the formula. $\newline$ $d(4)=3(-2)^{4-1}$
Simplify exponent: Simplify the exponent. $\newline$ Calculate the value of $(-2)^{(4-1)}$ , which is $(-2)^3$ . $\newline$ $(-2)^3 = -2 \times -2 \times -2 = -8$
Multiply by $3$ : Multiply the result by $3$ . Now, multiply the result from Step $3$ by $3$ as per the sequence formula. $d(4) = 3 \times (-8) = -24$