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The distance, DD in millions of miles of the voyager 11 space craft from the sun mm months after January 11 20152015 is approximately by the equation D=27.4m+12,100D=27.4m+12,100. What is the best interpretation of 27.427.4 as shown in the given equation?

Full solution

Q. The distance, DD in millions of miles of the voyager 11 space craft from the sun mm months after January 11 20152015 is approximately by the equation D=27.4m+12,100D=27.4m+12,100. What is the best interpretation of 27.427.4 as shown in the given equation?
  1. Interpret coefficient 27.427.4: The equation given is D=27.4m+12,100D = 27.4m + 12,100, where DD represents the distance in millions of miles and mm represents the number of months after January 11, 20152015. To interpret the coefficient 27.427.4, we need to understand its role in the equation.
  2. Multiplication with number of months: The coefficient 27.427.4 is multiplied by the number of months (m)(m). This suggests that for each month that passes, the distance of Voyager 11 from the sun increases by 27.427.4 million miles.
  3. Average speed of Voyager 11: Therefore, the best interpretation of 27.427.4 in this context is that it represents the average speed of Voyager 11 in millions of miles per month. This is the amount by which the distance from the sun increases each month.

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