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cosx(sin2x+sinx2)\frac{cosx}{(sin^2x+sinx-2)}

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Q. cosx(sin2x+sinx2)\frac{cosx}{(sin^2x+sinx-2)}
  1. Identify Trigonometric Identity: Step Title: Identify the Trigonometric Identity\newlineConcise Step Description: Recognize that the denominator is a quadratic in terms of sin(x)\sin(x) and can be factored.\newlineCalculation: No calculations in this step.
  2. Factor Denominator: Step Title: Factor the Denominator\newlineConcise Step Description: Factor the quadratic expression in the denominator.\newlineCalculation: We need to find two numbers that multiply to 2-2 (the constant term) and add to 11 (the coefficient of the middle term, sin(x)\sin(x)). The numbers that satisfy these conditions are 22 and 1-1.\newlineFactored form of the denominator: (sin(x)+2)(sin(x)1)(\sin(x) + 2)(\sin(x) - 1).
  3. Simplify Expression: Step Title: Simplify the Expression\newlineConcise Step Description: Write the simplified form of the expression with the factored denominator.\newlineCalculation: The expression becomes cos(x)(sin(x)+2)(sin(x)1)\frac{\cos(x)}{(\sin(x) + 2)(\sin(x) - 1)}.