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cos(2θ)=12\cos(2\theta) = \frac{1}{2}

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Q. cos(2θ)=12\cos(2\theta) = \frac{1}{2}
  1. Recognize Equation Involves Cosine: We need to solve the equation cos(2θ)=12\cos(2\theta) = \frac{1}{2}. The first step is to recognize that this equation involves the cosine of double the angle θ\theta. We need to find the values of θ\theta that satisfy this equation.
  2. Identify Specific Cosine Values: We know that the cosine function has a value of 12\frac{1}{2} at specific angles in the unit circle. These angles are 6060 degrees (or π3\frac{\pi}{3} radians) and 300300 degrees (or 5π3\frac{5\pi}{3} radians). However, since we are dealing with cos(2θ)\cos(2\theta), we need to find the angles for θ\theta such that when doubled, they give us the angles where the cosine is 12\frac{1}{2}.
  3. Find Theta Values: To find the values of theta, we divide the angles where cos(x)=12\cos(x) = \frac{1}{2} by 22. So, we get θ=60 degrees2=30 degrees\theta = \frac{60 \text{ degrees}}{2} = 30 \text{ degrees} (or \frac{\pi}{3} \text{ radians}}{2} = \frac{\pi}{6} \text{ radians}) and θ=300 degrees2=150 degrees\theta = \frac{300 \text{ degrees}}{2} = 150 \text{ degrees} (or \frac{5\pi}{3} \text{ radians}}{2} = \frac{5\pi}{6} \text{ radians}).
  4. Consider Periodicity: However, the cosine function is periodic with a period of 360360 degrees (or 2π2\pi radians), so we must consider all angles that are coterminal with 3030 degrees and 150150 degrees. This means we add k×360k\times360 degrees to each solution for θ\theta, where kk is an integer. In radians, we add k×2πk\times2\pi to each solution for θ\theta.
  5. General Solutions: Therefore, the general solutions for θ\theta are θ=30\theta = 30 degrees + k×360k\times360 degrees or θ=150\theta = 150 degrees + k×360k\times360 degrees, where kk is an integer. In radians, θ=π6+k×2π\theta = \frac{\pi}{6} + k\times2\pi or θ=5π6+k×2π\theta = \frac{5\pi}{6} + k\times2\pi, where kk is an integer.

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