Find (f@g)(-4) for the following functions. f(x)=4x-2" and "g(x)=x^(2) Answer How to enter your answer (opens in new window) (f@g)(-4)=

Understand Function Composition: First, we need to understand what (f@g)(x) means. The notation (f@g)(x) represents the composition of the functions f and g, which means we first apply g to x, and then apply f to the result of g(x). So, (f@g)(x) = f(g(x)). Let's start by finding g(-4).Calculate g(-4): Calculate g(-4) by substituting x with -4 in the function g(x) = x^2. g(-4) = (-4)^2 = 16.Find (f@g)(-4): Now that we have g(-4), we can find (f@g)(-4) by applying f to the result of g(-4). So we need to substitute x with 16 in the function f(x) = 4x - 2. f(g(-4)) = f(16) = 4(16) - 2.Calculate f(16): Calculate f(16) by multiplying 4 with 16 and then subtracting 2. f(16) = 4(16) - 2 = 64 - 2 = 62.

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Find
(f@g)(-4) for the following functions.

f(x)=4x-2" and "g(x)=x^(2)
Answer
How to enter your answer (opens in new window)

(f@g)(-4)=

$\newline$ Find $(f \circ g)(-4)$ for the following functions. $\newline$ $f(x)=4 x-2 \text { and } g(x)=x^{2}$ $\newline$ Answer $\newline$ How to enter your answer (opens in new window) $\newline$ $(f \circ g)(-4)=$

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Math Problems

Algebra 2

Find trigonometric ratios using reference angles

Full solution

\newline

Find

(f \circ g)(-4)

for the following functions.

\newline

f(x)=4 x-2 \text { and } g(x)=x^{2}

\newline

Answer

\newline

How to enter your answer (opens in new window)

\newline

(f \circ g)(-4)=

Understand Function Composition: First, we need to understand what $(f@g)(x)$ means. The notation $(f@g)(x)$ represents the composition of the functions $f$ and $g$ , which means we first apply $g$ to $x$ , and then apply $f$ to the result of $g(x)$ . So, $(f@g)(x) = f(g(x))$ . Let's start by finding $g(-4)$ .
Calculate $g(-4)$ : Calculate $g(-4)$ by substituting $x$ with $-4$ in the function $g(x) = x^2$ . $\newline$ $g(-4) = (-4)^2 = 16$ .
Find $(f@g)(-4)$ : Now that we have $g(-4)$ , we can find $(f@g)(-4)$ by applying $f$ to the result of $g(-4)$ . So we need to substitute $x$ with $16$ in the function $f(x) = 4x - 2$ . $\newline$ $f(g(-4)) = f(16) = 4(16) - 2$ .
Calculate $f(16)$ : Calculate $f(16)$ by multiplying $4$ with $16$ and then subtracting $2$ . $\newline$ $f(16) = 4(16) - 2 = 64 - 2 = 62$ .