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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)+2x-4
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x2+2x4 y=x^{2}+2 x-4 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x2+2x4 y=x^{2}+2 x-4 \newlineAnswer: y= y=
  1. Identify Quadratic Function: To complete the square for the quadratic function y=x2+2x4y = x^2 + 2x - 4, we first need to focus on the x2x^2 and 2x2x terms. We will add and subtract a certain value to create a perfect square trinomial.
  2. Determine Value to Add/Subtract: The value we need to add and subtract is determined by taking half of the coefficient of xx, which is 22, and then squaring it. (2/2)2=12=1(2/2)^2 = 1^2 = 1. So we will add and subtract 11 inside the parentheses.
  3. Rewrite Function with Perfect Square Trinomial: We rewrite the function as y=(x2+2x+1)14y = (x^2 + 2x + 1) - 1 - 4. We have added and subtracted 11 to complete the square.
  4. Factor Perfect Square Trinomial: Now, we can factor the perfect square trinomial as (x+1)2(x + 1)^2. So the function becomes y=(x+1)214y = (x + 1)^2 - 1 - 4.
  5. Combine Constants: Combine the constants 1-1 and 4-4 to simplify the function. y=(x+1)25y = (x + 1)^2 - 5.
  6. Convert to Vertex Form: The function is now in vertex form, y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. In this case, the vertex form is y=(x+1)25y = (x + 1)^2 - 5, with the vertex being (1,5)(-1, -5).

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