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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)-8x+5
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x28x+5 y=x^{2}-8 x+5 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x28x+5 y=x^{2}-8 x+5 \newlineAnswer: y= y=
  1. Identify Perfect Square Trinomial: To complete the square, we need to find a value that, when added and subtracted to the quadratic expression, forms a perfect square trinomial. The coefficient of x2x^2 is 11, so we only need to focus on the xx-term, which is 8x-8x. We take half of the coefficient of xx, which is 8/2=4-8/2 = -4, and square it to get 1616. This is the value we will add and subtract inside the parentheses.
  2. Add and Subtract Value: We rewrite the quadratic function by adding and subtracting 1616 inside the parentheses, and then we will move the constant term outside the parentheses.\newliney=x28x+1616+5y = x^2 - 8x + 16 - 16 + 5
  3. Group Trinomial and Constants: Now we group the perfect square trinomial and the constants separately.\newliney=(x28x+16)16+5y = (x^2 - 8x + 16) - 16 + 5
  4. Factor Perfect Square Trinomial: The perfect square trinomial (x28x+16)(x^2 - 8x + 16) can be factored into (x4)2(x - 4)^2, and we combine the constants 16-16 and +5+5.\newliney=(x4)211y = (x - 4)^2 - 11

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