Complete the square to re-write the quadratic function in vertex form: y=x^(2)-x-7 Answer: y=

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Complete the square to re-write the quadratic function in vertex form:  y=x^(2)-x-7 Answer:  y=

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Focus on x-terms: To complete the square and rewrite the quadratic function in vertex form, we first need to focus on the x-terms. The vertex form of a quadratic function is y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola. We will manipulate the given function to match this form.Find completing square value: The coefficient of x^2 is 1, which is already in the form we need. We will now take the coefficient of x, which is -1, divide it by 2, and square it to find the value that completes the square. (-1/2)^2 = 1/4Add/subtract to complete square: We add and subtract this value inside the parentheses to complete the square, making sure the equation remains balanced. y = x^2 - x + (1/4) - (1/4) - 7Rewrite equation with grouping: Now we can rewrite the equation grouping the x-terms and the constant that completes the square, and moving the other constants outside the parentheses. y = (x^2 - x + 1/4) - 1/4 - 7Factor perfect square trinomial: The expression inside the parentheses is now a perfect square trinomial, which can be factored into (x - 1/2)^2. y = (x - 1/2)^2 - 1/4 - 7Combine constants to simplify: Combine the constants -1/4 and -7 to simplify the equation. Since -7 is equivalent to -28/4, we have: y = (x - 1/2)^2 - 1/4 - 28/4 y = (x - 1/2)^2 - 29/4Quadratic function in vertex form: The quadratic function is now in vertex form, with the vertex being the point (h, k) = (1/2, -29/4).

Complete the square to re-write the quadratic function in vertex form: $\newline$ $y=x^{2}-x-7$ $\newline$ Answer: $y=$

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Complete the square to re-write the quadratic function in vertex form:\newliney=x2−x−7 y=x^{2}-x-7 y=x2−x−7\newlineAnswer: y= y= y=

Complete the square to re-write the quadratic function in vertex form: $\newline$ $y=x^{2}-x-7$ $\newline$ Answer: $y=$