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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)+x-10
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x2+x10 y=x^{2}+x-10 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x2+x10 y=x^{2}+x-10 \newlineAnswer: y= y=
  1. Focus on x2x^2 and xx terms: To complete the square and rewrite the quadratic function in vertex form, we first need to focus on the x2x^2 and xx terms. The vertex form of a quadratic function is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. We will complete the square for the xx terms to transform the given function into this form.
  2. Find completing square value: The coefficient of x2x^2 is 11, which is already in the form we need for completing the square. We will take the coefficient of xx, which is 11, divide it by 22, and then square it to find the value that completes the square.\newline(12)2=14(\frac{1}{2})^2 = \frac{1}{4}
  3. Add/subtract to complete square: We add and subtract this value inside the parentheses to complete the square. We must also ensure that we do not change the value of the expression by adding 14\frac{1}{4} and subtracting 14\frac{1}{4} (which effectively adds zero).\newliney=x2+x+(14)(14)10y = x^2 + x + \left(\frac{1}{4}\right) - \left(\frac{1}{4}\right) - 10
  4. Rewrite with completed square: Now we can rewrite the expression with the completed square and the constant terms grouped together.\newliney=(x2+x+14)1410y = (x^2 + x + \frac{1}{4}) - \frac{1}{4} - 10
  5. Factor perfect square trinomial: The expression in the parentheses is a perfect square trinomial, which can be factored into (x+12)2(x + \frac{1}{2})^2.\newliney = (x+12)21410(x + \frac{1}{2})^2 - \frac{1}{4} - 10
  6. Combine constant terms: Now we combine the constant terms 14-\frac{1}{4} and 10-10. Since 10-10 is the same as 404-\frac{40}{4}, we have:\newline14404=414-\frac{1}{4} - \frac{40}{4} = -\frac{41}{4}
  7. Substitute back into equation: Substitute the combined constant term back into the equation to get the vertex form of the quadratic function.\newliney=(x+12)2414y = (x + \frac{1}{2})^2 - \frac{41}{4}

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