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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)-6x+1
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x26x+1 y=x^{2}-6 x+1 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x26x+1 y=x^{2}-6 x+1 \newlineAnswer: y= y=
  1. Identify Coefficient and Half: To complete the square, we need to form a perfect square trinomial from the quadratic and linear terms of the function. The vertex form of a quadratic function is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Add and Subtract to Complete Square: First, we identify the coefficient of the xx term, which is 6-6. To form a perfect square trinomial, we take half of this coefficient, square it, and add it to and subtract it from the expression to maintain equality.\newlineHalf of 6-6 is 3-3, and (3)2(-3)^2 is 99.
  3. Group and Combine Constants: We add and subtract 99 within the function to complete the square:\newliney=x26x+99+1y = x^2 - 6x + 9 - 9 + 1
  4. Factor Perfect Square Trinomial: Now, we group the perfect square trinomial and combine the constants:\newliney=(x26x+9)8y = (x^2 - 6x + 9) - 8
  5. Rewrite in Vertex Form: The perfect square trinomial x26x+9x^2 - 6x + 9 can be factored into (x3)2(x - 3)^2:y=(x3)28y = (x - 3)^2 - 8
  6. Rewrite in Vertex Form: The perfect square trinomial x26x+9x^2 - 6x + 9 can be factored into (x3)2(x - 3)^2:y=(x3)28y = (x - 3)^2 - 8We have now rewritten the quadratic function in vertex form. The vertex form of the function is y=(x3)28.y = (x - 3)^2 - 8.

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