Complete the recursive formula of the geometric sequence 56,-28,14,-7,dots.. d(1)= d(n)=d(n-1)". "

Identify Common Ratio: To find the recursive formula for the geometric sequence, we first need to identify the common ratio by dividing any term by the term before it. Let's divide the second term by the first term: -28 ÷ 56 = -0.5Write Recursive Formula: Now that we have the common ratio, we can write the recursive formula. The first term d(1) is given as 56. So, d(1) = 56Calculate Recursive Part: For the recursive part, we know that each term is -0.5 times the previous term. Therefore, the recursive formula will be: d(n) = d(n-1) * -0.5 for n > 1

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Complete the recursive formula of the geometric sequence
56,-28,14,-7,dots..

d(1)=

d(n)=d(n-1)". "

Complete the recursive formula of the geometric sequence $\newline$ $56,-28,14,-7,\dots$ . $\newline$ $d(1)=$ $\newline$ $d(n)=d(n-1)\cdot$

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Math Problems

Grade 7

Write variable expressions for arithmetic sequences

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Q. Complete the recursive formula of the geometric sequence

\newline

56,-28,14,-7,\dots

\newline

d(1)=

\newline

d(n)=d(n-1)\cdot

Identify Common Ratio: To find the recursive formula for the geometric sequence, we first need to identify the common ratio by dividing any term by the term before it. $\newline$ Let's divide the second term by the first term: $-28 \div 56 = -0.5$
Write Recursive Formula: Now that we have the common ratio, we can write the recursive formula. The first term $d(1)$ is given as $56$ . So, $d(1) = 56$
Calculate Recursive Part: For the recursive part, we know that each term is $-0.5$ times the previous term. Therefore, the recursive formula will be: $\newline$ $d(n) = d(n-1) \times -0.5$ for n > 1