Complete the equation. Write the sum as a mixed number. (4)/(3)+(2)/(7)=(28)/(21)+(14)/(21)=◻(42)/(21)

Find Common Denominator: Step 1: Find a common denominator for the fractions (4/3) and (2/7). The least common multiple of 3 and 7 is 21. Convert (4/3) to (28/21) and (2/7) to (6/21). Calculation: (4/3) = (4*7)/(3*7) = (28/21), (2/7) = (2*3)/(7*3) = (6/21)Add Fractions: Step 2: Add the fractions with the common denominator. Add (28/21) and (6/21) to get (34/21). Calculation: (28/21) + (6/21) = (28+6)/21 = (34/21)Convert to Mixed Number: Step 3: Convert the improper fraction (34/21) to a mixed number. Divide 34 by 21 to get 1 with a remainder of 13. Calculation: 34 ÷ 21 = 1 R13, so (34/21) = 1 13/21

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Complete the equation. Write the sum as a mixed number.

(4)/(3)+(2)/(7)=(28)/(21)+(14)/(21)=◻(42)/(21)

Complete the equation. Write the sum as a mixed number. $\newline$ $\frac{4}{3}+\frac{2}{7}=\frac{28}{21}+\frac{14}{21}=\square \frac{42}{21}$

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Math Problems

Algebra 1

Multiplication with rational exponents

Full solution

Q. Complete the equation. Write the sum as a mixed number.

\newline

\frac{4}{3}+\frac{2}{7}=\frac{28}{21}+\frac{14}{21}=\square \frac{42}{21}

Find Common Denominator: Step $1$ : Find a common denominator for the fractions $(\frac{4}{3})$ and $(\frac{2}{7})$ . The least common multiple of $3$ and $7$ is $21$ . Convert $(\frac{4}{3})$ to $(\frac{28}{21})$ and $(\frac{2}{7})$ to $(\frac{6}{21})$ . Calculation: $(\frac{4}{3}) = (\frac{4\times7}{3\times7}) = (\frac{28}{21})$ , $(\frac{2}{7})$ $0$
Add Fractions: Step $2$ : Add the fractions with the common denominator. $\newline$ Add $(\frac{28}{21})$ and $(\frac{6}{21})$ to get $(\frac{34}{21})$ . $\newline$ Calculation: $(\frac{28}{21}) + (\frac{6}{21}) = \frac{28+6}{21} = (\frac{34}{21})$
Convert to Mixed Number: Step $3$ : Convert the improper fraction $(\frac{34}{21})$ to a mixed number. $\newline$ Divide $34$ by $21$ to get $1$ with a remainder of $13$ . $\newline$ Calculation: $34 \div 21 = 1 \, R13$ , so $(\frac{34}{21}) = 1 \frac{13}{21}$