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Cody was 
165cm tall on the first day of school this year, which was 
10% taller than he was on the first day of school last year.
How tall was Cody on the first day of school last year?

◻ 
cm

Cody was 165 cm 165 \mathrm{~cm} tall on the first day of school this year, which was 10% 10 \% taller than he was on the first day of school last year.\newlineHow tall was Cody on the first day of school last year?\newline______ cm \mathrm{cm}

Full solution

Q. Cody was 165 cm 165 \mathrm{~cm} tall on the first day of school this year, which was 10% 10 \% taller than he was on the first day of school last year.\newlineHow tall was Cody on the first day of school last year?\newline______ cm \mathrm{cm}
  1. Understand the problem: Understand the problem and what is being asked.\newlineCody was 165cm165\,\text{cm} tall on the first day of school this year, and this height is 10%10\% taller than his height on the first day of school last year. We need to find out Cody's height from last year.
  2. Set up the equation: Set up the equation to find Cody's height from last year.\newlineLet Cody's height from last year be xx cm. According to the problem, Cody's height this year (165165 cm) is 10%10\% taller than last year. This means that Cody's height this year is 110%110\% of last year's height. So, we can write the equation as:\newline110%110\% of x=165x = 165 cm
  3. Convert to decimal: Convert the percentage to a decimal to use it in the equation.\newline110%110\% as a decimal is 1.101.10. So the equation becomes:\newline1.10×x=1651.10 \times x = 165
  4. Solve for x: Solve for x to find Cody's height from last year.\newlineDivide both sides of the equation by 1.101.10 to isolate xx:\newlinex=1651.10x = \frac{165}{1.10}
  5. Perform division: Perform the division to calculate xx.x=150x = 150
  6. Verify solution: Verify the solution.\newlineIf Cody was 150cm150\,\text{cm} tall last year, then a 10%10\% increase would be 150cm×0.10=15cm150\,\text{cm} \times 0.10 = 15\,\text{cm}. Adding this increase to last year's height should give us this year's height:\newline150cm+15cm=165cm150\,\text{cm} + 15\,\text{cm} = 165\,\text{cm}\newlineSince this matches the given height for this year, our solution is correct.

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