Chase measured a line to be 2.8 inches long. If the actual length of the line is 2.9 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Chase measured a line to be 2.8 inches long. If the actual length of the line is 2.9 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand formula: Understand the percent error formula. Percent error is calculated using the formula:  Percent Error = (|Actual Value - Measured Value| / Actual Value) × 100 Here, the actual value is 2.9 inches, and the measured value is 2.8 inches.Plug in values: Plug in the values into the percent error formula. Percent Error = (|2.9 - 2.8| / 2.9) × 100Calculate absolute difference: Calculate the absolute difference between the actual value and the measured value. Absolute difference = |2.9 - 2.8| = 0.1 inchesDivide absolute difference: Divide the absolute difference by the actual value. Division result = 0.1 / 2.9Perform division: Perform the division to find the decimal form of the percent error. Division result = 0.034482758620689655 (This is a repeating decimal, but we will round it later.)Convert to percentage: Convert the decimal to a percentage. Percent Error = 0.034482758620689655 × 100Calculate percent error: Calculate the percent error as a percentage. Percent Error = 3.4482758620689655%Round to nearest tenth: Round the percent error to the nearest tenth of a percent. Rounded Percent Error = 3.4%

Chase measured a line to be $2$ . $8$ inches long. If the actual length of the line is $2$ . $9$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_______ $\%$

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Chase measured a line to be $2$ . $8$ inches long. If the actual length of the line is $2$ . $9$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_______ $\%$