Chad was asked whether the following equation is an identity:(3x+2y)2=(3x+2y)(3x−2y)+2(2y)2He performed the following steps:(3x+2y)2↪ Step 1=9x2+4y2↪ Step 2=9x2+4y2+4y2−4y2↪ Step 3=(9x2−4y2)+8y2↪ Step 4=(3x+2y)(3x−2y)+2(2y)2For this reason, Chad stated that the equation is a true identity.Is Chad correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Chad is correct.(B) Chad is incorrect. He made a mistake in step 1.(C) Chad is incorrect. He made a mistake in step 2.(D) Chad is incorrect. He made a mistake in step 4.
Q. Chad was asked whether the following equation is an identity:(3x+2y)2=(3x+2y)(3x−2y)+2(2y)2He performed the following steps:(3x+2y)2↪ Step 1=9x2+4y2↪ Step 2=9x2+4y2+4y2−4y2↪ Step 3=(9x2−4y2)+8y2↪ Step 4=(3x+2y)(3x−2y)+2(2y)2For this reason, Chad stated that the equation is a true identity.Is Chad correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Chad is correct.(B) Chad is incorrect. He made a mistake in step 1.(C) Chad is incorrect. He made a mistake in step 2.(D) Chad is incorrect. He made a mistake in step 4.
Expand using formula: Expand (3x+2y)2 using the formula (a+b)2=a2+2ab+b2.Calculation: (3x+2y)2=9x2+2⋅(3x)⋅(2y)+4y2=9x2+12xy+4y2.
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