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Camila bought stock in a company two years ago that was worth 
x dollars. During the first year that she owned the stock, it decreased by 
19%. During the second year the value of the stock decreased by 
8%. Write an expression in terms of 
x that represents the value of the stock after the two years have passed.
Answer:

Camila bought stock in a company two years ago that was worth x x dollars. During the first year that she owned the stock, it decreased by 19% 19 \% . During the second year the value of the stock decreased by 8% 8 \% . Write an expression in terms of x x that represents the value of the stock after the two years have passed.\newlineAnswer:

Full solution

Q. Camila bought stock in a company two years ago that was worth x x dollars. During the first year that she owned the stock, it decreased by 19% 19 \% . During the second year the value of the stock decreased by 8% 8 \% . Write an expression in terms of x x that represents the value of the stock after the two years have passed.\newlineAnswer:
  1. Understand the problem: Understand the problem.\newlineCamila's stock value decreases by 19%19\% in the first year and by 8%8\% in the second year. We need to find the expression that represents the value of the stock after these two decreases.
  2. Calculate first year value: Calculate the value of the stock after the first year.\newlineThe stock decreases by 19%19\% in the first year. To find the decreased value, we subtract 19%19\% of xx from xx.\newlineValue after first year = x(19100×x)x - (\frac{19}{100} \times x)
  3. Simplify first year expression: Simplify the expression for the value after the first year.\newlineValue after first year = x0.19xx - 0.19x\newlineValue after first year = 0.81x0.81x
  4. Calculate second year value: Calculate the value of the stock after the second year.\newlineThe stock decreases by 8%8\% in the second year. We apply this decrease to the value after the first year.\newlineValue after second year = 0.81x(8100×0.81x)0.81x - \left(\frac{8}{100} \times 0.81x\right)
  5. Simplify second year expression: Simplify the expression for the value after the second year.\newlineValue after second year = 0.81x0.08×0.81x0.81x - 0.08 \times 0.81x\newlineValue after second year = 0.81x0.0648x0.81x - 0.0648x\newlineValue after second year = 0.7452x0.7452x

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