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c(n)=-6+5(n-1) Find the 8^("th ") term in the sequence.

c(n)=−6+5(n−1) c(n)=-6+5(n-1) \newlineFind the 8th  8^{\text {th }} term in the sequence.

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Full solution

Q. c(n)=−6+5(n−1) c(n)=-6+5(n-1) \newlineFind the 8th  8^{\text {th }} term in the sequence.
  1. Substitute nn with 88: To find the 88th term in the sequence, we need to substitute nn with 88 in the given formula for c(n)c(n).\newlinec(n)=−6+5(n−1)c(n) = -6 + 5(n - 1)\newlinec(8)=−6+5(8−1)c(8) = -6 + 5(8 - 1)
  2. Simplify expression: Now we simplify the expression inside the parentheses.\newlinec(8)=−6+5(7)c(8) = -6 + 5(7)
  3. Multiply 55 by 77: Next, we multiply 55 by 77.c(8)=−6+35c(8) = -6 + 35
  4. Add −6-6 to 3535: Finally, we add −6-6 to 3535 to find the 88th term.\newlinec(8)=29c(8) = 29

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