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c(n)=(4)/(9)(-3)^(n-1)
What is the 
3^("rd ") term in the sequence?

c(n)=49(3)n1 c(n)=\frac{4}{9}(-3)^{n-1} \newlineWhat is the 3rd  3^{\text {rd }} term in the sequence?

Full solution

Q. c(n)=49(3)n1 c(n)=\frac{4}{9}(-3)^{n-1} \newlineWhat is the 3rd  3^{\text {rd }} term in the sequence?
  1. Identify term of sequence: Identify the term of the sequence we need to find.\newlineWe are asked to find the 3rd3^{\text{rd}} term in the sequence defined by the formula c(n)=(49)(3)n1c(n) = \left(\frac{4}{9}\right)(-3)^{n-1}.
  2. Substitute term number: Substitute the term number into the formula.\newlineTo find the 3rd3^{\text{rd}} term, we substitute n=3n=3 into the formula c(n)=(49)(3)(n1)c(n)=\left(\frac{4}{9}\right)(-3)^{(n-1)}.\newlinec(3)=(49)(3)(31)c(3)=\left(\frac{4}{9}\right)(-3)^{(3-1)}
  3. Calculate the exponent: Calculate the exponent.\newlineCalculate the value of (3)(31)(-3)^{(3-1)}, which is (3)2(-3)^2.\newline(3)2=9(-3)^2 = 9
  4. Multiply by coefficient: Multiply the result of the exponentiation by the coefficient.\newlineNow, multiply the result from Step 33 by the coefficient (49)(\frac{4}{9}).\newlinec(33)=(\frac{44}{99})\times 99
  5. Simplify the expression: Simplify the expression.\newlineSimplify the multiplication to find the 33rd term.\newlinec(3)=(49)9=4c(3)=\left(\frac{4}{9}\right)*9 = 4

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