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To solve the division problem, multiply by the reciprocal of the divisor.

(1)/(9)÷3=(1)/(9)×(1)/([?])

To solve the division problem, multiplyby the reciprocal of the divisor.\newline19÷3=19×1[?] \frac{1}{9} \div 3=\frac{1}{9} \times \frac{1}{[?]}

Full solution

Q. To solve the division problem, multiplyby the reciprocal of the divisor.\newline19÷3=19×1[?] \frac{1}{9} \div 3=\frac{1}{9} \times \frac{1}{[?]}
  1. Understand the problem: Understand the problem.\newlineWe need to divide the fraction 19\frac{1}{9} by the number 33. Division by a number is the same as multiplication by its reciprocal.
  2. Find the reciprocal: Find the reciprocal of the divisor.\newlineThe divisor is 33, and the reciprocal of 33 is 13\frac{1}{3}.
  3. Rewrite as multiplication: Rewrite the division as multiplication by the reciprocal.\newline(19)÷3=(19)×(13)(\frac{1}{9}) \div 3 = (\frac{1}{9}) \times (\frac{1}{3})
  4. Multiply numerators and denominators: Multiply the numerators and denominators.\newline(1×1)/(9×3)=1/27(1 \times 1) / (9 \times 3) = 1 / 27

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