Bruno is designing his next skateboard. The skateboard store has 3 types of grip tape, 13 types of decks, 7 types of trucks, 4 types of bearings, and 2 types of wheels. How many different skateboards can Bruno create? Assume each skateboard will contain only one type of each component.

Grip Tape Choices: Bruno has 3 choices for grip tape.Deck Choices: He has 13 choices for decks.Truck Choices: He has 7 choices for trucks.Bearing Choices: He has 4 choices for bearings.Wheel Choices: And he has 2 choices for wheels.Total Combinations: To find the total combinations, multiply the number of choices for each component. So, total combinations = 3 (grip tape) × 13 (decks) × 7 (trucks) × 4 (bearings) × 2 (wheels).Calculation: Calculating this gives us: 3 × 13 × 7 × 4 × 2 = 2184.

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Bruno is designing his next skateboard. The skateboard store has $3$ types of grip tape, $13$ types of decks, $7$ types of trucks, $4$ types of bearings, and $2$ types of wheels. $\newline$ How many different skateboards can Bruno create? Assume each skateboard will contain only one type of each component.

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Q. Bruno is designing his next skateboard. The skateboard store has

3

types of grip tape,

13

types of decks,

7

types of trucks,

4

types of bearings, and

2

types of wheels.

\newline

How many different skateboards can Bruno create? Assume each skateboard will contain only one type of each component.

Grip Tape Choices: Bruno has $3$ choices for grip tape.
Deck Choices: He has $13$ choices for decks.
Truck Choices: He has $7$ choices for trucks.
Bearing Choices: He has $4$ choices for bearings.
Wheel Choices: And he has $2$ choices for wheels.
Total Combinations: To find the total combinations, multiply the number of choices for each component. $\newline$ So, total combinations = $3$ (grip tape) $\times 13$ (decks) $\times 7$ (trucks) $\times 4$ (bearings) $\times 2$ (wheels).
Calculation: Calculating this gives us: $3 \times 13 \times 7 \times 4 \times 2 = 2184$ .