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Factor the quadratic equation: $x^{2}+6x+8=0$

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Solve complex trigonomentric equations

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Q. Factor the quadratic equation:

x^{2}+6x+8=0

Identify Quadratic Equation: Identify the quadratic equation to be solved. $\newline$ The given quadratic equation is $x^2 + 6x + 8 = 0$ . We need to find the values of $x$ that satisfy this equation.
Factor the Equation: Factor the quadratic equation. $\newline$ To factor the quadratic equation, we look for two numbers that multiply to give the constant term $8$ and add to give the coefficient of the $x$ term $6$ . The numbers $2$ and $4$ satisfy these conditions. $\newline$ So, we can write the equation as $(x + 2)(x + 4) = 0$ .
Set Equations Equal: Set each factor equal to zero and solve for $x$ . $\newline$ Since the product of the factors is zero, at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for $x$ : $\newline$ $x + 2 = 0$ or $x + 4 = 0$ .
Solve for x: Solve the first equation $x + 2 = 0$ . $\newline$ Subtracting $2$ from both sides of the equation $x + 2 = 0$ gives us $x = -2$ .
Final Solutions: Solve the second equation $x + 4 = 0$ . $\newline$ Subtracting $4$ from both sides of the equation $x + 4 = 0$ gives us $x = -4$ .

More problems from Solve complex trigonomentric equations

Question

Find all solutions with

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\newline

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\newline

\underline{\hspace{2em}}^\circ

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Question

Kimi's school is

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Question

-90^\circ < \theta < 90^\circ

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