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b(n)=-8-2(n-1)
Find the 
9^("th ") term in the sequence.

b(n)=82(n1) b(n)=-8-2(n-1) \newlineFind the 9th  9^{\text {th }} term in the sequence.

Full solution

Q. b(n)=82(n1) b(n)=-8-2(n-1) \newlineFind the 9th  9^{\text {th }} term in the sequence.
  1. Understanding the sequence formula: Understand the sequence formula.\newlineThe given sequence formula is b(n)=82(n1)b(n) = -8 - 2(n - 1). This is an arithmetic sequence where the first term is when n=1n = 1.
  2. Plugging in the value for the 99th term: Plug in the value for the 9th9^{\text{th}} term.\newlineTo find the 9th9^{\text{th}} term, we substitute n=9n = 9 into the sequence formula: b(9)=82(91)b(9) = -8 - 2(9 - 1).
  3. Simplifying the expression: Simplify the expression.\newlineSimplify the expression inside the parentheses first: b(9)=82(8)b(9) = -8 - 2(8).
  4. Performing the multiplication: Perform the multiplication.\newlineNow multiply 22 by 88: b(9)=816b(9) = -8 - 16.
  5. Combining like terms: Combine like terms.\newlineAdd the numbers together to get the 9th9^{\text{th}} term: b(9)=816=24b(9) = -8 - 16 = -24.

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