b(n)=4-6(n-1) Find the 4^("th ") term in the sequence.

Understand sequence formula: Understand the sequence formula. The given sequence is defined by the formula b(n) = 4 - 6(n - 1). This is an arithmetic sequence where the first term is 4 and the common difference is -6.Plug in value for 4th term: Plug in the value of n to find the 4th term. To find the 4th term, we substitute n = 4 into the formula: b(4) = 4 - 6(4 - 1).Perform calculation in parentheses: Perform the calculation inside the parentheses. Calculate the expression within the parentheses: 4 - 1 = 3.Multiply by -6: Multiply the result by -6. Now multiply -6 by the result from the previous step: -6 * 3 = -18.Subtract from 4: Subtract the result from 4. Finally, subtract -18 from 4 to find the 4th term: 4 - (-18) = 4 + 18 = 22.

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b(n)=4-6(n-1)
Find the
4^("th ") term in the sequence.

$b(n)=4-6(n-1)$ $\newline$ Find the $4^{\text {th }}$ term in the sequence.

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b(n)=4-6(n-1)

\newline

Find the

4^{\text {th }}

term in the sequence.

Understand sequence formula: Understand the sequence formula. $\newline$ The given sequence is defined by the formula $b(n) = 4 - 6(n - 1)$ . This is an arithmetic sequence where the first term is $4$ and the common difference is $-6$ .
Plug in value for $4$ th term: Plug in the value of $n$ to find the $4$ th term. $\newline$ To find the $4$ th term, we substitute $n = 4$ into the formula: $b(4) = 4 - 6(4 - 1)$ .
Perform calculation in parentheses: Perform the calculation inside the parentheses. $\newline$ Calculate the expression within the parentheses: $4 - 1 = 3$ .
Multiply by $-6$ : Multiply the result by $-6$ . $\newline$ Now multiply $-6$ by the result from the previous step: $-6 \times 3 = -18$ .
Subtract from $4$ : Subtract the result from $4$ . $\newline$ Finally, subtract $-18$ from $4$ to find the $4$ th term: $4 - (-18) = 4 + 18 = 22$ .