b(n)=-4-2(n-1) Find the 12^("th ") term in the sequence.

Identify formula for nth term: Identify the formula for the nth term of the sequence. The given formula is b(n) = -4 - 2(n - 1).Substitute n with 12: Substitute n with 12 to find the 12th term. b(12) = -4 - 2(12 - 1)Simplify expression inside parentheses: Simplify the expression inside the parentheses. b(12) = -4 - 2(11)Multiply 2 by 11: Multiply 2 by 11. b(12) = -4 - 2 * 11 b(12) = -4 - 22Add -4 and -22 to find 12th term: Add -4 and -22 to find the 12th term. b(12) = -4 - 22 b(12) = -26

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b(n)=-4-2(n-1)
Find the
12^("th ") term in the sequence.

$b(n)=-4-2(n-1)$ $\newline$ Find the $12^{\text {th }}$ term in the sequence.

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b(n)=-4-2(n-1)

\newline

Find the

12^{\text {th }}

term in the sequence.

Identify formula for nth term: Identify the formula for the nth term of the sequence. $\newline$ The given formula is $b(n) = -4 - 2(n - 1)$ .
Substitute $n$ with $12$ : Substitute $n$ with $12$ to find the $12$ th term. $b(12) = -4 - 2(12 - 1)$
Simplify expression inside parentheses: Simplify the expression inside the parentheses. $b(12) = -4 - 2(11)$
Multiply $2$ by $11$ : Multiply $2$ by $11$ . $\newline$ $b(12) = -4 - 2 \times 11$ $\newline$ $b(12) = -4 - 22$
Add $-4$ and $-22$ to find $12$ th term: Add $-4$ and $-22$ to find the $12$ th term. $b(12) = -4 - 22$ $b(12) = -26$