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b−6⋅b11=□b^{-6}\cdot b^{11}=\Box

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Full solution

Q. b−6⋅b11=□b^{-6}\cdot b^{11}=\Box
  1. Use Exponent Property: To solve b−6⋅b11b^{-6} \cdot b^{11}, we use the property of exponents that states when multiplying two powers with the same base, we add the exponents.\newlineCalculation: b−6⋅b11=b−6+11b^{-6} \cdot b^{11} = b^{-6 + 11}
  2. Add Exponents: Now we add the exponents −6-6 and 1111.\newlineCalculation: −6+11=5-6 + 11 = 5
  3. Simplify Expression: After adding the exponents, we get the simplified expression.\newlineCalculation: b−6⋅b11=b5b^{-6} \cdot b^{11} = b^5

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