Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Ayden deposits 
$290 every month into an account earning a monthly interest rate of 
0.7%. How much would he have in the account after 13 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Ayden deposits $290 \$ 290 every month into an account earning a monthly interest rate of 0.7% 0.7 \% . How much would he have in the account after 1313 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Ayden deposits $290 \$ 290 every month into an account earning a monthly interest rate of 0.7% 0.7 \% . How much would he have in the account after 1313 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify variables: Identify the variables from the problem.\newlineWe are given:\newlineMonthly deposit dd = $290\$290\newlineMonthly interest rate ii = 0.7%0.7\% or 0.0070.007 (as a decimal)\newlineNumber of years = 1313\newlineNumber of periods nn = 1313 years * 1212 months/year = $290\$29000 months
  2. Convert interest rate: Convert the interest rate to decimal form. 0.7%0.7\% as a decimal is 0.7/100=0.0070.7 / 100 = 0.007
  3. Calculate periods: Calculate the number of periods.\newlineSince Ayden deposits monthly and we are looking at a 1313-year period, we multiply the number of years by the number of months in a year.\newlinen=13 years×12 months/year=156 monthsn = 13 \text{ years} \times 12 \text{ months/year} = 156 \text{ months}
  4. Use formula for future value: Use the formula to calculate the future value of the account.\newlineA=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)\newlineA=$(290)×((1+0.007)15610.007)A = \$(290) \times \left(\frac{(1 + 0.007)^{156} - 1}{0.007}\right)
  5. Calculate future value: Calculate the future value using the values from the previous steps.\newlineA=($)290×((1+0.007)15610.007)A = (\$)290 \times \left(\frac{(1 + 0.007)^{156} - 1}{0.007}\right)\newlineA=($)290×((1.007)15610.007)A = (\$)290 \times \left(\frac{(1.007)^{156} - 1}{0.007}\right)
  6. Perform calculations: Perform the calculations inside the parentheses first.\newline(1.007)1561(1.007)^{156} - 1
  7. Calculate exponentiation: Calculate the exponentiation part of the formula.\newline(1.007)1562.03009(1.007)^{156} \approx 2.03009 (rounded to five decimal places for simplicity)
  8. Subtract from result: Subtract 11 from the result of the exponentiation.\newline2.0300911.030092.03009 - 1 \approx 1.03009
  9. Divide by interest rate: Divide the result by the interest rate.\newline1.03009/0.007147.155711.03009 / 0.007 \approx 147.15571
  10. Multiply by deposit amount: Multiply the result by the monthly deposit amount.\newlineA=($)290×147.15571A = (\$)290 \times 147.15571\newlineA($)42675.1559A \approx (\$)42675.1559
  11. Round final answer: Round the final answer to the nearest dollar.\newlineA$(42675)A \approx \$(42675) (to the nearest dollar)

More problems from Compound interest