Ava measured a line to be 8.7 inches long. If the actual length of the line is 9.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Ava measured a line to be 8.7 inches long. If the actual length of the line is 9.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand Percent Error: Understand the concept of percent error. Percent error is a measure of how inaccurate a measurement is, represented as a percentage of the actual value. The formula for percent error is: Percent Error = (|Actual Value - Measured Value| / Actual Value) × 100Identify Values: Identify the Actual Value and the Measured Value. In this problem, the Actual Value is 9.4 inches, and the Measured Value is 8.7 inches.Calculate Absolute Difference: Calculate the absolute difference between the Actual Value and the Measured Value. Absolute Difference = |Actual Value - Measured Value| = |9.4 - 8.7| = 0.7 inchesPlug into Formula: Plug the Absolute Difference and the Actual Value into the percent error formula. Percent Error = (0.7 / 9.4) × 100Perform Division and Multiplication: Perform the division and multiplication to find the percent error. Percent Error = (0.7 / 9.4) × 100 ≈ 7.4468...Round Percent Error: Round the percent error to the nearest tenth of a percent. Percent Error ≈ 7.4%

Ava measured a line to be $8$ . $7$ inches long. If the actual length of the line is $9$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:__________ $\%$

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Ava measured a line to be $8$ . $7$ inches long. If the actual length of the line is $9$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:__________ $\%$