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Audrey is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 
3.8% compounded quarterly. If Audrey would like to end up with 
$6,000 after 8 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Audrey is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 3.8% 3.8 \% compounded quarterly. If Audrey would like to end up with $6,000 \$ 6,000 after 88 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Audrey is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 3.8% 3.8 \% compounded quarterly. If Audrey would like to end up with $6,000 \$ 6,000 after 88 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify values: Identify the given values from the problem.\newlineAA (future value of the account) = $6,000\$6,000\newlineii (interest rate per period) = 3.8%3.8\% annual interest rate compounded quarterly, which is 3.8%4\frac{3.8\%}{4} per quarter\newlinenn (number of periods) = 88 years with quarterly contributions, which is 8×48 \times 4 quarters per year
  2. Convert interest rate: Convert the annual interest rate to a quarterly interest rate. i=3.8% per year4 quarters per year=0.0384=0.0095i = \frac{3.8\% \text{ per year}}{4 \text{ quarters per year}} = \frac{0.038}{4} = 0.0095 per quarter
  3. Calculate total periods: Calculate the total number of periods. n=8n = 8 years 4* 4 quarters per year =32= 32 quarters
  4. Use formula for amount: Use the formula to find the amount invested at the end of each period dd.A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)(\newline\)$6,000=d×((1+0.0095)3210.0095)\$6,000 = d \times \left(\frac{(1 + 0.0095)^{32} - 1}{0.0095}\right)
  5. Calculate inside parentheses: Calculate the value inside the parentheses.\newline(1+0.0095)321=(1.0095)321(1 + 0.0095)^{32} - 1 = (1.0095)^{32} - 1
  6. Calculate exponentiation: Calculate the exponentiation.\newline(1.0095)321.349858807576003(1.0095)^{32} \approx 1.349858807576003
  7. Subtract from result: Subtract 11 from the result of the exponentiation.\newline1.34985880757600310.3498588075760031.349858807576003 - 1 \approx 0.349858807576003
  8. Divide by interest rate: Divide the result by the interest rate per period.\newline0.349858807576003/0.009536.827243953263470.349858807576003 / 0.0095 \approx 36.82724395326347
  9. Solve for d: Solve for d by dividing the future value of the account by the result from the previous step.\newline$6,000/36.82724395326347162.974\$6,000 / 36.82724395326347 \approx 162.974
  10. Round result: Round the result to the nearest dollar. d$163d \approx \$163

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