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Aubree is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 
0.675%. If Aubree would like to end up with 
$7,000 after 2 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Aubree is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.675% 0.675 \% . If Aubree would like to end up with $7,000 \$ 7,000 after 22 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Aubree is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.675% 0.675 \% . If Aubree would like to end up with $7,000 \$ 7,000 after 22 years, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineA=$7,000A = \$7,000 (future value of the account)\newlinei=0.675%i = 0.675\% per month (interest rate per period)\newlinen=2n = 2 years 12* 12 months/year =24= 24 months (number of periods)\newlineWe need to find the value of dd (the amount invested at the end of each period).
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal. i=0.675%=0.675100=0.00675i = 0.675\% = \frac{0.675}{100} = 0.00675
  3. Plug Values into Formula: Plug the values into the formula to solve for dd.A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)$7,000=d×((1+0.00675)2410.00675)\$7,000 = d \times \left(\frac{(1 + 0.00675)^{24} - 1}{0.00675}\right)
  4. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+0.00675)241(1 + 0.00675)^{24} - 1\newline= (1.00675)241(1.00675)^{24} - 1\newline= 1.006752411.00675^{24} - 1\newline= 1.17797811.177978 - 1\newline= 0.1779780.177978
  5. Divide by Interest Rate: Divide the result by the interest rate ii.0.1779780.00675\frac{0.177978}{0.00675}=26.3691852= 26.3691852
  6. Divide Future Value by Result: Divide the future value AA by the result from Step 55 to solve for dd.$7,000/26.3691852=265.449\$7,000 / 26.3691852 = 265.449
  7. Round Monthly Contribution: Round the monthly contribution to the nearest dollar. \newlined$265d \approx \$265 (to the nearest dollar)

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