At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in $10,875 in ticket sales one evening. If each child ticket costs $7.50 and each adult ticket costs $10.00, how many adult tickets were sold that evening?◻
Q. At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in $10,875 in ticket sales one evening. If each child ticket costs $7.50 and each adult ticket costs $10.00, how many adult tickets were sold that evening?◻
Denote Tickets and Sales: Let's denote the number of child tickets sold as C and the number of adult tickets sold as A. We are given two equations based on the total number of tickets and the total sales:1. C+A=1,200 (total tickets)2. 7.50C+10A=10,875 (total sales in dollars)We need to solve this system of equations to find the value of A, the number of adult tickets sold.
Rearrange First Equation: First, we can rearrange the first equation to express C in terms of A:C=1,200−AThis will allow us to substitute the value of C in the second equation.
Substitute C in Second Equation: Now, let's substitute C=1,200−A into the second equation:7.50(1,200−A)+10A=10,875This will give us an equation with one variable, A, which we can solve for.
Distribute and Simplify: Let's distribute 7.50 into the parentheses and simplify the equation:7.50×1,200−7.50A+10A=10,8759,000−7.50A+10A=10,875Now, we combine like terms:9,000+2.50A=10,875
Isolate Term with A: Next, we subtract 9,000 from both sides to isolate the term with A:2.50A=10,875−9,0002.50A=1,875Now, we divide both sides by 2.50 to solve for A:A=2.501,875
Solve for A: Performing the division gives us the number of adult tickets sold: A=750 So, 750 adult tickets were sold that evening.
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