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At Charlie's Cinema, a total of 1,200 adult and child movie tickets were sold to bring in $10,875 in ticket sales one evening. If each child ticket costs $7.50 and each adult ticket costs $10.00, how many adult tickets were sold that evening?

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At Charlie's Cinema, a total of 1,2001,200 adult and child movie tickets were sold to bring in $10,875\$10,875 in ticket sales one evening. If each child ticket costs $7.50\$7.50 and each adult ticket costs $10.00\$10.00, how many adult tickets were sold that evening?\newline

Full solution

Q. At Charlie's Cinema, a total of 1,2001,200 adult and child movie tickets were sold to bring in $10,875\$10,875 in ticket sales one evening. If each child ticket costs $7.50\$7.50 and each adult ticket costs $10.00\$10.00, how many adult tickets were sold that evening?\newline
  1. Denote Tickets and Sales: Let's denote the number of child tickets sold as CC and the number of adult tickets sold as AA. We are given two equations based on the total number of tickets and the total sales:\newline11. C+A=1,200C + A = 1,200 (total tickets)\newline22. 7.50C+10A=10,8757.50C + 10A = 10,875 (total sales in dollars)\newlineWe need to solve this system of equations to find the value of AA, the number of adult tickets sold.
  2. Rearrange First Equation: First, we can rearrange the first equation to express CC in terms of AA:C=1,200AC = 1,200 - AThis will allow us to substitute the value of CC in the second equation.
  3. Substitute CC in Second Equation: Now, let's substitute C=1,200AC = 1,200 - A into the second equation:\newline7.50(1,200A)+10A=10,8757.50(1,200 - A) + 10A = 10,875\newlineThis will give us an equation with one variable, AA, which we can solve for.
  4. Distribute and Simplify: Let's distribute 7.507.50 into the parentheses and simplify the equation:\newline7.50×1,2007.50A+10A=10,8757.50 \times 1,200 - 7.50A + 10A = 10,875\newline9,0007.50A+10A=10,8759,000 - 7.50A + 10A = 10,875\newlineNow, we combine like terms:\newline9,000+2.50A=10,8759,000 + 2.50A = 10,875
  5. Isolate Term with A: Next, we subtract 9,0009,000 from both sides to isolate the term with AA:\newline2.50A=10,8759,0002.50A = 10,875 - 9,000\newline2.50A=1,8752.50A = 1,875\newlineNow, we divide both sides by 2.502.50 to solve for AA:\newlineA=1,8752.50A = \frac{1,875}{2.50}
  6. Solve for A: Performing the division gives us the number of adult tickets sold: A=750A = 750 So, 750750 adult tickets were sold that evening.

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