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At a shop, a mobile phone was sold at 40%40\% of a television. Both items were sold at a 20%20\% discount. Janet paid $2016\$2016 for both items after the discount. What was the usual price of the television?

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Q. At a shop, a mobile phone was sold at 40%40\% of a television. Both items were sold at a 20%20\% discount. Janet paid $2016\$2016 for both items after the discount. What was the usual price of the television?
  1. Define Variables: First, let's define the variables:\newlineLet TT be the usual price of the television.\newlineThe mobile phone was sold at 40%40\% of the price of the television, so the price of the mobile phone is 0.40T0.40T.\newlineBoth items were sold at a 20%20\% discount.\newlineJanet paid $2016\$2016 for both items after the discount.\newlineWe need to find the value of TT.
  2. Calculate Prices After Discount: Calculate the price of both items after the 2020% discount.\newlineThe discount on the television is 2020% of TT, which is 0.20T0.20T.\newlineThe discounted price of the television is T0.20T=0.80TT - 0.20T = 0.80T.\newlineThe discount on the mobile phone is 2020% of 0.40T0.40T, which is 0.08T0.08T.\newlineThe discounted price of the mobile phone is 0.40T0.08T=0.32T0.40T - 0.08T = 0.32T.
  3. Combine Discounted Prices: Combine the discounted prices of both items to set up the equation based on the total amount paid by Janet.\newlineTotal cost after discount = Discounted price of television + Discounted price of mobile phone\newline$2016=0.80T+0.32T\$2016 = 0.80T + 0.32T
  4. Simplify Equation: Simplify the equation to solve for TT.
    $2016=0.80T+0.32T\$2016 = 0.80T + 0.32T
    $2016=1.12T\$2016 = 1.12T
  5. Divide to Find Price: Divide both sides of the equation by 1.121.12 to find the usual price of the television.\newlineT=$20161.12T = \frac{\$2016}{1.12}\newlineT=$1800T = \$1800

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