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At a local bakery, Edgar decorated 66 cakes at a time. Javier decorated 88 at a time. If they ended up decorating the same number of cakes by the end of the day, what is the smallest number of cakes that each must have decorated?\newline\newline_____cakes

Full solution

Q. At a local bakery, Edgar decorated 66 cakes at a time. Javier decorated 88 at a time. If they ended up decorating the same number of cakes by the end of the day, what is the smallest number of cakes that each must have decorated?\newline\newline_____cakes
  1. Identify Concept: Identify the mathematical concept needed to solve the problem. We need to find the smallest number of cakes that both Edgar and Javier could have decorated, which means finding the Least Common Multiple (LCM) of the numbers of cakes they decorated at a time, 66 and 88.
  2. List Multiples: List the multiples of 66 and 88 to find the LCM.\newlineMultiples of 66: 6,12,18,24,30,36,42,486, 12, 18, 24, 30, 36, 42, 48\ldots\newlineMultiples of 88: 8,16,24,32,40,488, 16, 24, 32, 40, 48\ldots\newlineThe smallest common multiple of 66 and 88 is 2424.
  3. Verify Calculation: Verify the calculation by checking if 2424 is divisible by both 66 and 88. \newline24÷6=424 \div 6 = 4\newline24÷8=324 \div 8 = 3\newlineBoth divisions result in whole numbers, confirming that 2424 is indeed the LCM.

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