Ashley measured a line to be 6.3 inches long. If the actual length of the line is 6.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Ashley measured a line to be 6.3 inches long. If the actual length of the line is 6.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand percent error formula: Understand the percent error formula. Percent error is calculated using the formula:  Percent Error = (|Actual Value - Measured Value| / Actual Value) × 100% Here, the actual value is 6.4 inches, and the measured value is 6.3 inches.Calculate absolute difference: Calculate the absolute difference between the actual value and the measured value. Absolute difference = |6.4 - 6.3| = |0.1| = 0.1 inchesDivide absolute difference: Divide the absolute difference by the actual value. Divide 0.1 inches by 6.4 inches to get the error in decimal form. 0.1 / 6.4 = 0.015625Convert decimal error to percentage: Convert the decimal error to a percentage. Multiply the decimal error by 100 to get the percent error. 0.015625 × 100% = 1.5625%Round percent error: Round the percent error to the nearest tenth of a percent. Rounding 1.5625% to the nearest tenth of a percent gives us 1.6%.

Ashley measured a line to be $6$ . $3$ inches long. If the actual length of the line is $6$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ________ $\%$

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Ashley measured a line to be $6$ . $3$ inches long. If the actual length of the line is $6$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ________ $\%$