Arianna deposits $450 every month into an account earning a monthly interest rate of 0.525%. How much would she have in the account after 24 months, to the nearest dollar? Use the following formula to determine your answer. A=d(((1+i)^(n)-1)/(i)) A= the future value of the account after n periods d= the amount invested at the end of each period i= the interest rate per period n= the number of periods Answer:

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Arianna deposits  $450 every month into an account earning a monthly interest rate of  0.525%. How much would she have in the account after 24 months, to the nearest dollar? Use the following formula to determine your answer.  A=d(((1+i)^(n)-1)/(i))  A= the future value of the account after  n periods  d= the amount invested at the end of each period  i= the interest rate per period  n= the number of periods Answer:

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Identify Given Values: Identify the given values from the problem. Arianna deposits $450 every month, so d = $450. The monthly interest rate is 0.525%, so i = 0.525/100 = 0.00525. The number of periods is 24 months, so n = 24.Convert Interest Rate: Convert the interest rate to a decimal. i = 0.525% = 0.525/100 = 0.00525Substitute Values: Substitute the values into the formula. A = d * (((1 + i)^(n) - 1) / i) A = 450 * (((1 + 0.00525)^(24) - 1) / 0.00525)Calculate Future Value: Calculate the future value of the account after 24 periods. A = 450 * (((1 + 0.00525)^(24) - 1) / 0.00525) A = 450 * (((1.00525)^(24) - 1) / 0.00525)Perform Exponentiation: Perform the exponentiation. (1.00525)^(24) ≈ 1.13269Continue Calculation: Continue the calculation. A = 450 * ((1.13269 - 1) / 0.00525) A = 450 * (0.13269 / 0.00525)Complete Division and Multiplication: Complete the division and multiplication. A = 450 * (25.274285714285715) A ≈ 11373.428571428572Round Final Answer: Round the final answer to the nearest dollar. A ≈ $11373

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