Answer: C Q.6: The product of 82 and 5 is: A. 400 B. 410 C. 420

Identify Operation: Identify the operation required to solve the problem. We need to find the product of 82 and 5, which means we need to multiply 82 by 5.Perform Multiplication: Perform the multiplication. To find the product, we multiply 82 by 5. 82 * 5 = 410Verify Calculation: Verify the calculation to ensure there are no math errors. Double-checking the multiplication: 10 * 5 = 50 (for the units place) 80 * 5 = 400 (for the tens place) Adding them together: 50 + 400 = 450 Upon rechecking, we find that there is a math error in the previous step.

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Answer: C
Q.6: The product of 82 and 5 is:
A. 400
B. 410
C. 420

Answer: C $\newline$ Q. $6$ : The product of $82$ and $5$ is: $\newline$ A. $400$ $\newline$ B. $410$ $\newline$ C. $420$

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Math Problems

Algebra 1

Unions and intersections of sets

Full solution

Q. Answer: C

\newline

6

: The product of

82

and

5

is:

\newline

400

\newline

410

\newline

420

Identify Operation: Identify the operation required to solve the problem. $\newline$ We need to find the product of $82$ and $5$ , which means we need to multiply $82$ by $5$ .
Perform Multiplication: Perform the multiplication. $\newline$ To find the product, we multiply $82$ by $5$ . $\newline$ $82 \times 5 = 410$
Verify Calculation: Verify the calculation to ensure there are no math errors. $\newline$ Double-checking the multiplication: $\newline$ $10 \times 5 = 50$ (for the units place) $\newline$ $80 \times 5 = 400$ (for the tens place) $\newline$ Adding them together: $50 + 400 = 450$ $\newline$ Upon rechecking, we find that there is a math error in the previous step.