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An object is launched from a platform.
Its height (in meters), 
x seconds after the launch, is modeled by:

h(x)=-5x^(2)+20 x+60
What is the height of the object at the time of launch?

An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by:\newlineh(x)=5x2+20x+60h(x)=-5x^{2}+20x+60\newlineWhat is the height of the object at the time of launch?

Full solution

Q. An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by:\newlineh(x)=5x2+20x+60h(x)=-5x^{2}+20x+60\newlineWhat is the height of the object at the time of launch?
  1. Evaluate height function: To find the height of the object at the time of launch, we need to evaluate the height function h(x)h(x) at x=0x = 0, which represents the time of launch.\newlineCalculation: h(0)=5(0)2+20(0)+60h(0) = -5(0)^2 + 20(0) + 60
  2. Calculate height at launch: Simplifying the expression, we get h(0)=5(0)+20(0)+60=0+0+60=60h(0) = -5(0) + 20(0) + 60 = 0 + 0 + 60 = 60 meters.

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