An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by h(x)=-5(x+1)(x-9) What is the height of the object at the time of launch? ◻ meters

Evaluate at x=0: To find the height of the object at the time of launch, we need to evaluate the function h(x) at x = 0, since the time of launch corresponds to the initial time, which is 0 seconds after the launch.Substitute x=0: Substitute x = 0 into the height function h(x) = -5(x+1)(x-9). h(0) = -5(0+1)(0-9)Perform multiplication: Perform the multiplication inside the parentheses. h(0) = -5(1)(-9)Find height at launch: Multiply the numbers together to find the height at the time of launch. h(0) = -5 * 1 * -9 h(0) = 45

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An object is launched from a platform.
Its height (in meters), x seconds after the launch, is modeled by

h(x)=-5(x+1)(x-9)
What is the height of the object at the time of launch?

◻ meters

An object is launched from a platform. $\newline$ Its height (in meters), $x$ seconds after the launch, is modeled by $\newline$ $h(x)=-5(x+1)(x-9)$ $\newline$ What is the height of the object at the time of launch? $\newline$ $\square$ $\text{meters}$

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Q. An object is launched from a platform.

\newline

Its height (in meters),

x

seconds after the launch, is modeled by

\newline

h(x)=-5(x+1)(x-9)

\newline

What is the height of the object at the time of launch?

\newline

\square

\text{meters}

Evaluate at $x=0$ : To find the height of the object at the time of launch, we need to evaluate the function $h(x)$ at $x = 0$ , since the time of launch corresponds to the initial time, which is $0$ seconds after the launch.
Substitute $x=0$ : Substitute $x = 0$ into the height function $h(x) = -5(x+1)(x-9)$ . $\newline$ $h(0) = -5(0+1)(0-9)$
Perform multiplication: Perform the multiplication inside the parentheses. $\newline$ $h(0) = -5(1)(-9)$
Find height at launch: Multiply the numbers together to find the height at the time of launch. $\newline$ $h(0) = -5 \times 1 \times -9$ $\newline$ $h(0) = 45$