Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents who own exactly three of these things. Find the number of residents of Aimeville who own all four of these things.
Q. Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents who own exactly three of these things. Find the number of residents of Aimeville who own all four of these things.
Denote Residents: Let's denote the number of residents who own all four items as x. According to the problem, there are 437 residents who own exactly two of these things and 234 residents who own exactly three of these things. Since every resident owns a bag of candy hearts, we only need to consider the other three items when determining the overlaps.
Use Inclusion-Exclusion Principle: We can use the principle of inclusion-exclusion to find the number of residents who own all four items. The formula for three sets A, B, and C is given by:∣A∪B∪C∣=∣A∣+∣B∣+∣C∣−∣A∩B∣−∣A∩C∣−∣B∩C∣+∣A∩B∩C∣In this context, ∣A∪B∪C∣ is the total number of residents who own at least one of the three items (diamond ring, golf clubs, garden spade), ∣A∣, ∣B∣, and ∣C∣ are the numbers of residents who own each item individually, ∣A∩B∣, ∣A∩C∣, and ∣B∩C∣ are the numbers of residents who own exactly two of the items, and B0 is the number we're looking for, B1.
Calculate Total Residents: First, we calculate the total number of residents who own at least one of the three items (diamond ring, golf clubs, garden spade). Since every resident owns a bag of candy hearts, we can ignore it for this calculation. The total number of residents is 900, so:∣A∪B∪C∣=900
Plug in Values: Now we plug in the values we know into the inclusion-exclusion formula:900=195+367+562−∣A∩B∣−∣A∩C∣−∣B∩C∣+xWe know that ∣A∩B∣+∣A∩C∣+∣B∩C∣ includes the residents who own exactly two items and those who own all three items. Since there are 437 residents who own exactly two items and 234 who own exactly three, we can express this as:∣A∩B∣+∣A∩C∣+∣B∩C∣=437+234
Find Value of x: Substituting the value of ∣A∩B∣+∣A∩C∣+∣B∩C∣ into the inclusion-exclusion formula, we get:900=195+367+562−(437+234)+xNow we perform the calculations:900=1124−671+x900=453+x
Find Value of x: Substituting the value of ∣A∩B∣+∣A∩C∣+∣B∩C∣ into the inclusion-exclusion formula, we get:900=195+367+562−(437+234)+xNow we perform the calculations:900=1124−671+x900=453+xTo find the value of x, we subtract 453 from both sides of the equation:x=900−453x=447
More problems from Unit prices with fractions and decimals